题解 | #合并两个排序的链表#

/*
 * function ListNode(x){
 *   this.val = x;
 *   this.next = null;
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param pHead1 ListNode类 
 * @param pHead2 ListNode类 
 * @return ListNode类
 */
function Merge( pHead1 ,  pHead2 ) {
    // write code here
    if(!pHead1)return pHead2
    if(!pHead2)return pHead1
    if(pHead1.val <= pHead2.val){
        pHead1.next = Merge(pHead1.next,pHead2)
        return pHead1
    }else{
        pHead2.next = Merge(pHead2.next,pHead1)
        return pHead2
    }
}
module.exports = {
    Merge : Merge
};