题解 | #小美的因子查询#
小美的因子查询
https://www.nowcoder.com/practice/1870e68256794c6aa727c8bb71fd9737
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a;
for(int i = 1; i <= a; i++){
cin >> b;
if(b & 1)cout << "NO\n";
else cout << "YES\n";
}
}
// 64 位输出请用 printf("%lld")
