题解 | #删除字符串中出现次数最少的字符#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    while ((line = await readline())) {
        const arr = line.split("");
        //obj用于存储字符串中每个字符和出现的次数
        let obj = {};
        arr.forEach((key) => {
            if (obj[key]) {
                obj[key] += 1;
            } else {
                obj[key] = 1;
            }
        });
        let min = Math.min(...Object.values(obj));
        //finalArr用来接收最后去掉出现次数最少字符后的数组
        let finalArr = [];
        finalArr = arr.filter((val) => {
            return obj[val] !== min;
        });
        console.log(finalArr.join(''));
    }
})();