题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899?tpId=383&tags=&title=&difficulty=0&judgeStatus=0&rp=0&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E5%25AD%25A6%25E4%25B9%25A0%25E7%25AF%2587%26topicId%3D383
#include <iostream>
using namespace std;
int main() {
int a;
int hour, minate, seconds;
cin >> a;
hour = a/3600;
minate = (a - hour*3600) / 60;
seconds = a % 60;
cout << hour <<" " << minate <<" " << seconds << endl;
return 0;
}
// 64 位输出请用 printf("%lld")
，养生
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