题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
if (n%2!=0) {
printf("%d",(n+1)/2);
}
else {
printf("%d",-(n/2));
}
}
根据交错级数求和公式可直接写出


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