题解 | #百鸡问题#

#include<iostream>
using namespace std;
int main() {
    int n;
    cin >> n;
    for (int i = 0; i <= 100; ++i) {
        for (int j = 0; j <= (100 - i); ++j) {
            for (int k = 0; k <= (100 - j - i); ++k) {
                if ((n - (5 * i + 3 * j)) * 3 - k >= 0 && (i + j + k) == 100) {
                    cout << "x=" << i << "," << "y=" << j << "," << "z=" << k << endl;
                }

            }
        }
    }

    return 0;
}