题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h>
int main() {
int x, y, x1, y1;
scanf("%d%d%d%d", &x, &y, &x1, &y1);
if (y1 - y == 1)
printf("u");
if (y1 - y == -1)
printf("d");
if (x1 - x == 1)
printf("r");
if (x1 - x == -1)
printf("l");
return 0;
}
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