题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input())
mat1 = [[1,2,3],[4,5,6],[7,8,9]]
for i in range(len(mat1)):
    for j in range(len(mat1[i])):       
        mat1[i][j] *= n
print(mat1)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input())
mat1 = [[1,2,3],[4,5,6],[7,8,9]]
for i in range(len(mat1)):
    for j in range(len(mat1[i])):       
        mat1[i][j] *= n
print(mat1)
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