题解 | #打印日期#

#include<iostream>
using namespace std;

int daytab[2][31] = {
    {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
};

int main() {
    int year;
    int count;
    int month, day;
    int flag = -1;

    while (cin >> year >> count) {
        flag = (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
        for (int i = 1; i < 13; i++) {
            if (count - daytab[flag][i] > 0) {
                count -= daytab[flag][i];
                continue;
            } else if (count - daytab[flag][i] == 0) {
                month = i;
                day = daytab[flag][i];
                break;
            } else {
                month = i;
                day = count;
                break;
            }
        }
        printf("%d-%02d-%02d\n", year, month, day);
        //0表示左边补0，2表示位宽
        //字符串格式化各种精度/补0
        //https://www.cnblogs.com/lidabo/p/5463179.html
        //%[标志][输出最小宽度][.精度][长度]类型
    }
}

C语言格式化字符串：https://www.cnblogs.com/lidabo/p/5463179.html

%[标志][输出最小宽度][.精度][长度]类型