题解 | 字符串合并处理
字符串合并处理
https://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
import sys
# 处理合法十六进制并返回数字
def solve(c):
#先转十进制
t = int(c,16)
#然后转二进制补零
b = f"{t:04b}"
#取反后转字符串
b = ''.join(reversed(b))
#二进制转十进制
t = int(b,2)
#十进制转十六进制
res = f"{t:x}".upper()
# print(res)
return res
for line in sys.stdin:
a = line.split()
s = [x for x in (a[0]+a[1])]
s[::2] = sorted(s[::2])
s[1::2] = sorted(s[1::2])
res = ''
for c in s:
if c.isdigit():
c1 = solve(c)
res+=c1
elif c.isalpha() and c.lower()>='a' and c.lower()<='f':
c1 = solve(c)
res+=c1
else:
res+=c
print(res)

