题解 | 牛牛的时钟

#include <stdio.h>
const int base[1][3] = {0, 0, 0};

int main() {
    int i, n, j;
    int time[100][3] = {};
    int t[100] = {};//存输入时间
    int s, m, h;
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        scanf("%d", &t[i]);
    }
    for (i = 0; i < n; i++) {
        //分割时分秒
        s = t[i] % 60;
        m = (t[i] / 60) % 60;
        h = (int)((t[i] / 3600) % 24);
        //时间累加
        if (i == 0) {
            time[i][2] = time[i][2] + s;
            time[i][1] = time[i][1] + m;
            time[i][0] = time[i][0] + h;
        } else {
            time[i][2] = time[i - 1][2] + s;
            time[i][1] = time[i - 1][1] + m;
            time[i][0] = time[i - 1][0] + h;
        }
        //处理溢出，从秒开始
        for (j = 2; j >= 0; j--) {
            if (time[i][j] >= 60) {
                time[i][j - 1] += time[i][j] / 60; 
                time[i][j] = time[i][j] % 60;
            }
        }
    }
    for (i = 0; i < n; i++) {
        printf("%d %d %d\n", time[i][0], time[i][1], time[i][2]);
    }
    return 0;
}