题解 | #单链表的排序#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#
class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here
        h = head
        l = []
        while h:
            l.append(h.val)
            h = h.next
        l.sort()

        dummy = ListNode(0)
        current = dummy
        for i in l:
            current.next = ListNode(i)
            current = current.next
        return dummy.next