题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
# 列表生成式秒了 matix = [[1,2,3], [4,5,6], [7,8,9]] a=int(input()) n=[] for i in matix: n.append([a * x for x in i]) print(n)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
# 列表生成式秒了 matix = [[1,2,3], [4,5,6], [7,8,9]] a=int(input()) n=[] for i in matix: n.append([a * x for x in i]) print(n)
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