题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
dic = {}
def pop_minstr(n):
for i in n:
dic[i] = n.count(i) #统计每个字符出现的次数
for k,v in dic.items():
if v == min(dic.values()): # 拿每个字符出现的次数与出现最少次数作比较
for num in range(v): # 出现次数最少的字符出现几次，则就需要删几次
n.remove(k)
return ''.join(n)
n = list(input())
print(pop_minstr(n))
