题解 | #水仙花数#

#include <stdio.h>

int main()
{
	int m[2] = { 0 };//2个范围
	int n[2] = { 0 };//2个范围
	int sum[2] = { 0 };//存储有多少水仙花熟
	int arr[3] = { 0 };//存储数位
	scanf("%d %d", &m[0], &n[0]);
	//删除的scanf
	for (int x = 0; x < 1; x++)//处理2次(被例子骗了,写了个无意义的循环,x从2改了1
	{
		for (int i = m[x]; i <= n[x]; i++)
		{
			int h = i;

			for (int j = 0; h > 0; j++)
			{
				arr[j] = h % 10;
				h = h / 10;
			}
			if (pow(arr[0], 3) + pow(arr[1], 3) + pow(arr[2], 3) == i)
			{
				printf("%d ", i);
				sum[x] = sum[x] + 1;
			}


		}
		if (sum[x] == 0)
		{
			printf("no\n");
		}
		else
		{
			printf("\n");
		}
	}
	
	return 0;
}