题解 | #牛牛学数列#
牛牛学数列
https://ac.nowcoder.com/acm/problem/22156
#include<cstdio>
int main(){
  int n;
  scanf("%d",&n);
  if(n&1)printf("%d",1-(--n/2)+n);
  else printf("-%d",n>>1);
}
题解 文章被收录于专栏
 https://ayx.moefox.tech/
牛牛学数列
https://ac.nowcoder.com/acm/problem/22156
#include<cstdio>
int main(){
  int n;
  scanf("%d",&n);
  if(n&1)printf("%d",1-(--n/2)+n);
  else printf("-%d",n>>1);
}
https://ayx.moefox.tech/
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