题解 | #跳台阶#

public class Solution { public int jumpFloor(int target) { if(target == 1) return 1; if(target == 2) return 2; //其实就是跳上前1阶台阶的数量加上前2阶台阶的数量 return jumpFloor(target-1) + jumpFloor(target - 2); } }