题解 | #数字颠倒#
数字颠倒
http://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <string.h>
#include<iostream>
using namespace std;
int main()
{
int a = 0;
while (cin >> a)
{
if(a==0)
{
cout << 0;
}
else
{
int b[100] = { 0 };
int d = 0;
while(a)
{
b[d] = (a % 10);
d++;
a = a / 10;
}
for (int i = 0; i < d; i++)
cout << b[i];
}
}
return(0);
}
#include<iostream>
using namespace std;
int main()
{
int a = 0;
while (cin >> a)
{
if(a==0)
{
cout << 0;
}
else
{
int b[100] = { 0 };
int d = 0;
while(a)
{
b[d] = (a % 10);
d++;
a = a / 10;
}
for (int i = 0; i < d; i++)
cout << b[i];
}
}
return(0);
}