题解 | 在字符串中找出连续最长的数字串

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String l = in.nextLine();
            // String[] lines = l.split("[a-z]");

            // int max = 0;
            // int[] index = new int[lines.length];
            // for (int i = 0; i < lines.length; i ++) {
            //     index[i] = lines[i].length();
            //     max = Math.max(index[i], max);
            // }

            // for (int i = 0; i < lines.length; i ++) {
            //     if (index[i] == max) {
            //         System.out.print(lines[i]);
            //     }
            // }
            // System.out.print("," + max);

            int[] dp = new int [l.length() + 1];
            int max = 0;

            for (int i = 1; i <= l.length(); i++) {
                if (Character.isDigit(l.charAt(i-1))) {
                    dp[i] = dp[i - 1] + 1;
                    if (dp[i] > max) {
                        max = dp[i];
                    }
                } else {
                    dp[i] = 0;
                }
            }

            for (int i = 1; i < l.length()+1; i++) {
                if (max == dp[i]) {
                    System.out.print(l.substring(i - max, i));
                }
            }
            System.out.print("," + max);
        }
    }
}