题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include<stdio.h>
int main()
{
int seconds;
int s=0;
int h=0;
int m=0;
int a=0;
scanf ("%d\n",&seconds);
if (seconds>0&&seconds<100000000)
{
a=(seconds-seconds%60)/60;
s=seconds%60;
h=(a-a%60)/60;
m=(seconds-h*3600-s)/60;
printf ("%d %d %d\n",h,m,s);
}
return 0;
}
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