题解 | #单组_spj判断数组之和#
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
# 读取输入
n, m = map(int, input().split())
# 初始化数组，所有元素设为1
array = [1] * n
# 计算还需要多少才能达到总和m
remainder = m - n
# 如果remainder大于0，则将其加到数组的最后一个元素上
if remainder > 0:
array[-1] += remainder
# 输出数组
print(' '.join(map(str, array)))
#python#