题解 | #记负均正#

#include <stdio.h>

int main() {
    int arr[2000]={0};
    int n=0;
    scanf("%d",&n);
    int sum=0;
    int count1=0;
    int count2=0;
    for(int i=0;i<n;i++)
    {
        scanf("%d",&arr[i]);
        if(arr[i]<0)
        count1++;
        else if(arr[i]>0)
        {
            count2++;
            sum=sum+arr[i];
        }
    }
    double mid=0.0;
    if(count2)
    {
        mid=(double)sum/(double)count2;
    }
    printf("%d %.1f",count1,mid);
    return 0;
}