题解 | #日期类#

#include <iostream>

using namespace std;

int daytab[2][13] = {
{
	0,31,28,31,30,31,30,31,31,30,31,30,31	
},
{
	0,31,29,31,30,31,30,31,31,30,31,30,31
}
};

bool isLeapYear(int x){
	return (x % 4 ==0 && x % 100 != 0) || (x % 400 == 0);
}

int main(){
	int n,y,m,d;
	cin >> n;
	
	while(n --){
		cin >> y >> m >> d;
		if(d < daytab[isLeapYear(y)][m]){
			d ++;
		}else{
			if(m == 12){
				y ++;
			}else{
				m ++;
				d = 1;
			}
		}
		printf("%04d-%02d-%02d\n",y,m,d);
	}
	return 0;
}