题解 | #简单计算器#
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include<stdio.h>
int main()
{
double n1 = 0.0;
double n2 = 0.0;
char opt = '0';
while (scanf("%lf %c %lf", &n1, &opt, &n2) != EOF)
{
switch (opt)
{
case '+':
printf("%.4lf+%.4lf=%.4lf", n1 ,n2 ,n1+n2);
break;
case'-':
printf("%.4lf-%.4lf=%.4lf", n1 , n2,n1-n2);
break;
case'*':
printf("%.4lf*%.4lf=%.4lf", n1 ,n2,n1*n2);
break;
case'/':
if (n2 == 0.0)
{
printf("Wrong!Division by zero!\n");
break;
}
else
{
printf("%.4lf/%.4lf=%.4lf", n1 ,n2 , n1/n2);
break;
}
default:
printf("Invalid operation!\n");
break;
}
}
return 0;
}


