题解 | #字符逆序#
字符逆序
https://www.nowcoder.com/practice/cc57022cb4194697ac30bcb566aeb47b
#include <stdio.h>
#include <string.h>
#define N 10010
char s[N];
void reverse(char* s)
{
int n = strlen(s);
for (int i = 0; i < n / 2; i ++ )
{
char c = s[i];
s[i] = s[n - i - 1];
s[n - i - 1] = c;
}
}
int main()
{
scanf("%[^\n]", s);
reverse(s);
for (int i = 0; i < strlen(s); i ++ ) printf("%c", s[i]);
return 0;
}
