题解 | #上三角矩阵判定#
上三角矩阵判定
https://www.nowcoder.com/practice/f5a29bacfc514e5a935723857e1245e4
n = int(input())
lst = [list(map(int,input().split())) for i in range(n)]
flag = 1
for i in range(n):
for j in range(i):
if lst[i][j] != 0:
flag = 0
break
if flag:
print('YES')
else:
print('NO')
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