题解 | #KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
#include <stdio.h>
int main()
{
int i = 0;
int x = 0;
for (i=100; i<=999; i++)
{
int j = 0;
int n = 0;
for(j=2; j<i; j++)
{
if (i%j==0)
break;
else
n++;
}
if (n==i-2)
{
x++;
}
}
printf("%d",x);
return 0;
}
