题解 | #小乐乐改数字#
小乐乐改数字
https://www.nowcoder.com/practice/fcd30aac9c4f4028b23919a0c649824d
#include <stdio.h>
#include<math.h>
int main() {
int n,m=0;
scanf("%d", &n);
for (int i = 0; n != 0; i++) {
m= (n%2)*pow(10,i)+m;
n = n / 10;
}
printf("%d",m);
return 0;
}
