题解 | #密码强度等级#

while True:
    try:
        keyword = input()

        #判断密码长度
        count = 0
        if len(keyword) <= 4:
            count += 5
        elif 5 <= len(keyword) <= 7:
            count += 10
        else:
            count += 25

        #判断密码包含字母数量
        a,b,c = 0,0,0
        for i in keyword:
            if ord('a') <= ord(i) <= ord('z'):
                b += 1
                a += 1
            elif ord('A') <= ord(i) <= ord('Z'):
                c += 1
                a += 1
        if a == 0:
            count += 0
        elif b == 0 and c != 0 or b != 0 and c == 0:
            count += 10
        elif b != 0 and c != 0:
            count += 20

        #判断密码包含数字数量
        d = 0
        for i in keyword:
            if i.isdigit():
                d += 1
        if d == 0:
            count += 0
        elif d == 1:
            count += 10
        else:
            count += 20

        #判断密码包含符号数量
        e,f,g = 0,0,0
        for i in keyword:
            if i.isalpha():
                e += 1
            elif i.isdigit():
                f += 1
        g = e+f
        if g == len(keyword):
            count += 0
        elif len(keyword)-g == 1:
            count += 10
        else:
            count += 25

        #奖励
        if (b != 0 and c != 0) and d != 0 and g != 0:
            count += 5
        elif (b == 0 and c != 0 or b != 0 and c == 0) and d != 0 and g != 0:
            count += 3
        elif a != 0 and d != 0:
            count += 2


        #输出内容，也可以简化一下
        if count >= 90:
            print("VERY_SECURE")
        elif count >= 80:
            print('SECURE')
        elif count >= 70:
            print('VERY_STRONG')
        elif count >= 60:
            print('STRONG')
        elif count >= 50:
            print('AVERAGE')
        elif count >= 25:
            print('WEAK')
        else:
            print('VERY_WEAK')
        
    except:
        break