题解 | #计算日期到天数转换#

#include <iostream>
using namespace std;

int main() {
    int run[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
    int burun[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int n,y,r;
    int num = 0;
    cin>>n>>y>>r;
    if(n%4==0){
        if(n%100==0){
            if(n%400==0){
                for(int i = 0;i<y-1;i++){
                    num += run[i];
                }
                num+=r;
                cout<<num;
            }else{
                for(int i = 0;i<y-1;i++){
                    num += burun[i];
                }
                num+=r;
                cout<<num;
            }
        }else{
            for(int i = 0;i<y-1;i++){
                    num += run[i];
                }
                num+=r;
                cout<<num;
        }
        
    }else{
        for(int i = 0;i<y-1;i++){
                    num += burun[i];
                }
                num+=r;
                cout<<num;
    }

}
// 64 位输出请用 printf("%lld")