题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
反转链表
思路:cur.next = pre
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
# @param head ListNode类
# @return ListNode类
class Solution:
def ReverseList(self , head: ListNode) -> ListNode:
# write code here
# 空链表处理
if head == None:
return head
# 非空链表处理
pre = None
cur = head
while cur:
tmp = cur.next
cur.next = pre
pre = cur
cur = tmp
return pre


