题解 | #取近似值#
取近似值
https://www.nowcoder.com/practice/3ab09737afb645cc82c35d56a5ce802a
#include <iostream>
using namespace std;
int main() {
double n;
cin>>n;
double re=n-(int)n;
if(re>=0.5)cout<<(int)n+1;
else cout<<(int)n;
return 0;
}
// 64 位输出请用 printf("%lld")
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