深信服9.1笔试
题比较简单，直接上代码
1.准备一个额外空间，，存放比较胜者，直接比较过去，记录比较次数
nt main1()
{
vector<int>arr;
int t = 0;
while (cin>>t)
{
arr.push_back(t);
if (cin.get() == '\n')
{
break;
}
}
int k = arr[arr.size() - 1];
arr.pop_back();
int left = 1;
int comnum = arr[0];
int cnt = 0;
while (left < arr.size())
{
if (comnum > arr[left])
{
cnt++;
}
else
{
cnt = 1;
comnum = arr[left];
}
left++;
if (cnt == k)
{
break;
}
}
string s = to_string(comnum);
cout << s;
system("pause");
return 0;
} 2.最长连续序列********128 int lonest(vector<int>& v)
{
int res = 0;
unordered_set<int>rec(v.begin(), v.end());
for (auto n : rec)
{
if (rec.count(n - 1))
{
continue;
}
int cnt = 1;
while (rec.count(++n))
{
++cnt;
}
res = max(res, cnt);
}
return res;
}
int main2()
{
int n;
cin >> n;
vector<int>arr;
while (n--)
{
int a;
cin >> a;
arr.push_back(a);
}
if (arr.size() == 1)
{
return arr.size();
}
cout << lonest(arr) << endl;
system("pause");
return 0;
}
3.第三题遍历数组，维护最大值与最小值，当最大值与最小值的差大于2*x，伪装次数加1，最大最小值变为当前遍历值 int main()
{
int n, x;
cin >> n >> x;
vector<int>arr;
while (n--)
{
int a;
cin >> a;
arr.push_back(a);
}
int res = 0;
int maxarr = arr[0];
int minarr = arr[0];
for (int i = 0; i < arr.size(); i++)
{
maxarr = max(maxarr, arr[i]);
minarr = min(minarr, arr[i]);
if (maxarr - minarr > 2 * x)
{
res++;
maxarr = arr[i];
minarr = arr[i];
}
}
cout << res << endl;
system("pause");
return 0;
} 