题解 | #字符逆序#
求最小公倍数
http://www.nowcoder.com/practice/22948c2cad484e0291350abad86136c3
let [A, B] = readline().split(' ').map(x => Number(x));
let min = A < B ? A : B;
let max = A > B ? A : B;
if(max % min == 0) {
console.log(max);
} else {
let x = min * max;
for(let i = min; i <= x; i++) {
if(i % A == 0 && i % B == 0) {
console.log(i);
break;
}
}
}