题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
比较无脑的方法，子查询套娃，用一个窗口函数
select name,grade_num from
(SELECT name,grade_num,dense_rank()over(ORDER BY grade_num desc) G from
(select id,name,sum(grade_num) grade_num FROM `user` u join grade_info gi on u.id=gi.user_id
group by id,name) as A
) as B
WHERE G=1
