题解 | #连续子数组的最大和(二)#
连续子数组的最大和(二)
http://www.nowcoder.com/practice/11662ff51a714bbd8de809a89c481e21
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param array int整型一维数组
* @return int整型一维数组
*/
public int[] FindGreatestSumOfSubArray (int[] array) {
if(array.length == 1) return array;
// write code here
int snapLeft = 0,snapRight = 0;
int left = 0, right = 0;
int maxSum = Integer.MIN_VALUE, maxLength = 0;
int dp[] = new int[array.length];
dp[0] = array[0];
for(int i = 1; i < array.length; i++) {
right ++;
dp[i] = Math.max(dp[i-1] + array[i],array[i]);
if(dp[i-1] + array[i] < array[i]) left = right;
// 快照
if(dp[i] > maxSum || dp[i] == maxSum && right - left + 1 > maxLength) {
snapLeft = left;
snapRight = right;
maxSum = dp[i];
maxLength = right - left + 1;
}
}
int[] res = new int[maxLength];
for(int i = 0; i < maxLength; i++) {
res[i] = array[snapLeft++];
}
return res;
}
}
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