题解 | #求平方根#
求平方根
http://www.nowcoder.com/practice/09fbfb16140b40499951f55113f2166c
class Solution {
public:
/**
*
* @param x int整型
* @return int整型
*/
int sqrt(int x) {
int l = 0, r = x, ans = -1;
while (l <= r) {
int mid = l + (r - l) / 2;
if ((long long)mid * mid <= x) {
ans = mid;
l = mid + 1;
} else {
r = mid - 1;
}
}
return ans;
// write code here
}
};
https://leetcode-cn.com/problems/sqrtx/solution/x-de-ping-fang-gen-by-leetcode-solution/
查看6道真题和解析