题解 | #牛客每个人最近的登录日期(一)#
牛客每个人最近的登录日期(一)
http://www.nowcoder.com/practice/ca274ebe6eac40ab9c33ced3f2223bb2
方法1 用max函数
select user_id, max(date)
from login
group by user_id
order by user_id asc;
方法2 用窗口函数， distinct去重
select distinct user_id, first_value(date) over (partition by user_id order by date desc) as d
from login;
from login;