题解 | DNA序列

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    char DNA[1010] = {0};
    int n;
    fgets(DNA, sizeof(DNA), stdin);
    DNA[strcspn(DNA, "\n")] = '\0';
    scanf("%d\n", &n);

    float max_gcRatio = 0;
    int index = 0;

    for (int i = 0; DNA[i + n - 1] != '\0'; i++)
    {
        float gcRatio = 0;
        int count = 0;
        for (int j = 0; j < n; j++)
        {
            if (DNA[i + j] == 'G' || DNA[i + j] == 'C')
            {
                count++;
            }
        }
        gcRatio = (float)count / n;
        if (gcRatio > max_gcRatio)
        {
            max_gcRatio = gcRatio;
            index = i;
        }
    }

    for (int i = 0; i < n; i++)
    {
        printf("%c", DNA[i + index]);
    }

    return 0;
}