题解 | 占空比50%的奇数分频
占空比50%的奇数分频
https://www.nowcoder.com/practice/ccfba5e5785f4b3f9d7ac19ab13d6b31
`timescale 1ns / 1ns module odo_div_or ( input wire rst, input wire clk_in, output wire clk_out7 ); //*************code***********// reg [2:0] cnt_p, cnt_n; reg clk_p, clk_n; assign clk_out7 = clk_p | clk_n; always @(posedge clk_in or negedge rst) begin if (!rst) begin cnt_p <= 0; end else if (cnt_p == 'd6) begin cnt_p <= 0; end else begin cnt_p <= cnt_p + 1; end end always @(posedge clk_in or negedge rst) begin if (!rst) begin clk_p <= 0; end else if (cnt_p == 'd3) begin clk_p <= 1; end else if (cnt_p == 'd6) begin clk_p <= 0; end end always @(negedge clk_in or negedge rst) begin if (!rst) begin cnt_n <= 0; end else if (cnt_n == 'd6) begin cnt_n <= 0; end else begin cnt_n <= cnt_n + 1; end end always @(negedge clk_in or negedge rst) begin if (!rst) begin clk_n <= 0; end else if (cnt_n == 'd3) begin clk_n <= 1; end else if (cnt_n == 'd6) begin clk_n <= 0; end end //*************code***********// endmodule
注意两个边界条件:中点(7-1)>>2=3处的01转变和cnt=6时的10转变