题解 | 字符串合并处理
字符串合并处理
https://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
u = list((input().replace(" ", "")))
u[0::2] = sorted(u[0::2])
u[1::2] = sorted(u[1::2])
v = []
valid_hex_chars = set('0123456789ABCDEFabcdef')
for c in u:
if c in valid_hex_chars:
binary_reversed = int(bin(int(c, 16))[2:].rjust(4, '0')[::-1], 2)
v.append(hex(binary_reversed)[2:].upper())
else:
v.append(c)
print("".join(v))
