题解 | 查找输入整数二进制中1的个数

import sys

n = int(input())
m = int(input())

nn = []
mm = []
while n > 0:
    if n % 2 == 0:
        nn.append(0)
        n = n // 2
    if n % 2 == 1:
        nn.append(1)
        n = n // 2
while m > 0:
    if m % 2 == 0:
        mm.append(0)
        m = m // 2
    if m % 2 == 1:
        mm.append(1)
        m = m // 2
print(nn.count(1))
print(mm.count(1))