题解 | 简单计算器

记得使用双精度，否则会有一组报错。

#include <stdio.h>

int main() {
    char ch;
    double a,b;
    scanf("%lf%c%lf",&a,&ch,&b);
    if(ch=='+'||ch=='-'||ch=='*'||ch=='/'){
        switch (ch) {
            case '+':printf("%.4lf+%.4lf=%.4lf\n",a,b,a+b);break;
            case '-':printf("%.4lf-%.4lf=%.4lf\n",a,b,a-b);break;
            case '*':printf("%.4lf*%.4lf=%.4lf\n",a,b,a*b);break;
            case '/':
            if(b == 0.0){
                printf("Wrong!Division by zero!\n");break;
            }
            else{
                printf("%.4lf/%.4lf=%.4lf\n",a,b,a/b);break;
            }
        }
    }
    else{
        printf("Invalid operation!");
    }
    return 0;
}