题解 | 0级用户高难度试卷的平均用时和平均得分

select
    er.uid,
    round(avg(if (score is null, 0, score)), 0) avg_score,
    round(
        avg(
            truncate (
                if (
                    submit_time is null,
                    duration,
                    (timestampdiff (second, start_time, submit_time)) / 60
                ),
                0
            )
        ),
        1
    ) avg_time_took
from
    test.user_info ui
    join test.exam_record er on ui.uid = er.uid
    join test.examination_info ei on er.exam_id = ei.exam_id
where
    level = 0
    and difficulty = 'hard'
group by
    uid

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牛客583549203号:腾讯还好,况且实习而已,实习生流动性很大,属于正常现象,记得和HR委婉解释
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