题解 | 简单计算器

#include <stdio.h>
int main()
{
	char ch;
	double a,b;
	scanf("%lf %c %lf",&a,&ch,&b);
	switch(ch)
	{
		case '+':
			printf("%.4lf+%.4lf=%.4lf",a,b,a+b);
			break;
		case '-':
			printf("%.4lf-%.4lf=%.4lf",a,b,a-b);
			break;
		case '*':
			printf("%.4lf*%.4lf=%.4lf",a,b,a*b);
			break;
		case '/':
			if(b==0){
			printf("Wrong!Division by zero!");
			break;}
			else{
			printf("%.4lf/%.4lf=%.4lf",a,b,a*1.0/b);
			break;}
		default:
			printf("Invalid operation!");
			break;
	}
	return 0;
}
	

这道题不用输入字符串比较容易解答，使用switch也能做