题解 | 查找输入整数二进制中1的个数
def ten_to_two(n1):
n = int(n1)
m = bin(n)
sum = 0
for i in map(int,m[2:]):
if i == 1:
sum += 1
return sum
while True:
try:
print(ten_to_two(input().strip()))
except:
break
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