题解 | #skew数#写个while循环就行
skew数
https://www.nowcoder.com/practice/5928127cc6604129923346e955e75984
while True: try: n = int(input()) ans = 0 i = 1 while n: ans += n % 10 * (2 ** i - 1) n //= 10 i += 1 print(ans) except: break
skew数
https://www.nowcoder.com/practice/5928127cc6604129923346e955e75984
while True: try: n = int(input()) ans = 0 i = 1 while n: ans += n % 10 * (2 ** i - 1) n //= 10 i += 1 print(ans) except: break
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