题解 | #小乐乐改数字#

#include <stdio.h>
    int main()
{
int i = 0, n, k, c = 0;
    int ret=0;
    scanf("%d", &n);
    k = n;
    int a[20];
    while (k) {
        i++;
        k = k / 10;
        c++;
    }
    int d = 0;
    for (int m = 0; m < i; m++) {
        if (n % 2 == 1) {
            a[d++] = 1;
            n = n / 10;
        } else if (n % 2 == 0) {
            a[d++] = 0;
            n = n / 10;
        }
    }
    for (int g = c - 1; g >= 0; g--)
        ret=ret*10+a[g];
        printf("%d",ret);
    return 0;

}