换个方式

整数与IP地址间的转换

https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        System.out.println(ip2num(sc.nextLine()));

        System.out.println(num2ip(sc.nextLong()));


    }

    public static long ip2num(String ip) {
        String[] split = ip.split("\\.");
        StringBuilder builder = new StringBuilder();
        for (int i = 0; i < split.length; i++) {
            String binaryString = Integer.toBinaryString(Integer.parseInt(split[i]));
            for (int j = 0; j < 8 - binaryString.length(); j++) {
                builder.append("0");
            }
            builder.append(binaryString);
        }
        // 指定多少进制转换为10进制
        return Long.parseLong(builder.toString(), 2);
    }

    public static String num2ip(long num) {
        String binaryString = Long.toBinaryString(num);
        StringBuilder builder = new StringBuilder();
        for (int i = 0; i < 32 - binaryString.length(); i++) {
            builder.append("0");
        }
        builder.append(binaryString);

        String[] strings = new String[4];
        for (int i = 0; i < 4; i++) {
            // 从2进制转成10进制
            long parseLong = Long.parseLong(builder.substring(i * 8, (i * 8) + 8),2);
            strings[i] = parseLong + "";
        }
        return String.join(".", strings);
    }
}

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