换个方式
整数与IP地址间的转换
https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println(ip2num(sc.nextLine())); System.out.println(num2ip(sc.nextLong())); } public static long ip2num(String ip) { String[] split = ip.split("\\."); StringBuilder builder = new StringBuilder(); for (int i = 0; i < split.length; i++) { String binaryString = Integer.toBinaryString(Integer.parseInt(split[i])); for (int j = 0; j < 8 - binaryString.length(); j++) { builder.append("0"); } builder.append(binaryString); } // 指定多少进制转换为10进制 return Long.parseLong(builder.toString(), 2); } public static String num2ip(long num) { String binaryString = Long.toBinaryString(num); StringBuilder builder = new StringBuilder(); for (int i = 0; i < 32 - binaryString.length(); i++) { builder.append("0"); } builder.append(binaryString); String[] strings = new String[4]; for (int i = 0; i < 4; i++) { // 从2进制转成10进制 long parseLong = Long.parseLong(builder.substring(i * 8, (i * 8) + 8),2); strings[i] = parseLong + ""; } return String.join(".", strings); } }