题解 | #简单密码#

#include <iostream>
#include <bits/stdc++.h>
using namespace std;

int main() {
    string str;
    char c;
    int n;
    cin >> str;
    for(int i = 0; i < str.size(); i++){
        if(str[i]>= 'a' && str[i] <= 'z'){
            n = (str[i] <= 'c')?2: (str[i] <= 'f')?3:(str[i] <= 'i')?4:(str[i] <= 'l')?5:(str[i] <= 'o')?6:(str[i] <= 's')?7:(str[i] <= 'v')?8:(str[i] <= 'z')?9:str[i];
            cout << n;
        }
        else if (str[i]>= 'A' && str[i] <= 'Z'){
            if (str[i] == 'Z') cout << 'a';
            else {
                c = 'a' + (str[i] - 'A' + 1);
                cout << c;
                }
        }
        else {
            cout << str[i];
        }
    }
    cout << endl;
}
// 64 位输出请用 printf("%lld")